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JEE Mains · Maths · STD 11 - 3. trignometrical ratios,functions and identities

ધારો કે તમામ \(\mathrm{a} \in \mathrm{R}\) નો ગણ એવો છે કે જેથી સમીકરણ \(\cos 2 x+a \sin x=2 \mathrm{a}-7\), ને ઉકેલ \([\mathrm{p}, \mathrm{q}]\) છે અને \(\mathrm{r}=\tan 9^{\circ}-\tan 27^{\circ}-\frac{1}{\cot 63^{\circ}}+\tan 81^{\circ}\). તો \(pqr\) \(=\) ...........

  1. A \(62\)
  2. B \(55\)
  3. C \(48\)
  4. D \(45\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(48\)

Step-by-step Solution

Detailed explanation

\(\cos 2 x+a \cdot \sin x=2 a-7 \) \( a(\sin x-2)=2(\sin x-2)(\sin x+2) \) \( \sin x=2, \quad a=2(\sin x+2) \) \( \Rightarrow a \in[2,6] \) \( p=2 \quad q=6\) \( r=\tan 9^{\circ}+\cot 9^{\circ}-\tan 27-\cot 27 \)…
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