ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 7.2 definite integral

ધારો કે \(\mathrm{f}: \mathrm{R} \rightarrow \mathrm{R}\) \(f(x)=\frac{x}{\left(1+x^4\right)^{1 / 4}}\) વડે વ્યાખ્યાયિત વિધેય છે અને \(g(x)=f(f(f(f(x))))\) છે. તો \(18 \int_0^{\sqrt{2 \sqrt{5}}} x^2 g(x) d x\) = ...........

  1. A \(33\)
  2. B \(36\)
  3. C \(42\)
  4. D \(39\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(39\)

Step-by-step Solution

Detailed explanation

\( f(x)=\frac{x}{\left(1+x^4\right)^{1 / 4}} \) \( f \circ f(x)=\frac{f(x)}{\left(1+f(x)^4\right)^{1 / 4}}=\frac{\frac{x}{\left(1+x^4\right)^{1 / 4}}}{\left(1+\frac{x^4}{1+x^4}\right)^{1 / 4}}=\frac{x}{\left(1+2 x^4\right)^{1 / 4}}\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app