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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

ધારો કે \(A\) એ \(3\times3\) એ સામાન્ય શ્રેણીક છે અને \((A - 3I) (A- 5I)\, = 0\), કે જ્યાં \(I\,= I_3\) અને \(O\,= O_3\). જો \(\alpha A + \beta A^{- 1}\, = 4I\), તો \(\alpha + \beta  = . .. \)

  1. A \(8\)
  2. B \(12\)
  3. C \(13\)
  4. D \(7\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(8\)

Step-by-step Solution

Detailed explanation

we have \((A-3I)(A-5I)=0\) \( \Rightarrow {A^2} - 8A + 15I = 0\) Multiplying both sides by \({A^{ - 1}}\), we get; \({A^{ - 1}}A.A - 8{A^{ - 1}}A + 15{A^{ - 1}}I = {A^{ - 1}}0\) \( \Rightarrow A - 8I + 15{A^{ - 1}} = 0\) \(A + 15{A^{ - 1}} = 8I\)…
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