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JEE Mains · Maths · STD 11 - 4.1 complex nubers

ધારો કે \(\alpha=8-14 i, A=\left\{z \in C : \frac{\alpha z-\bar{\alpha} \bar{z}}{z^2-(\bar{z})^2-112 i}=1\right\}\) અને \(B=[z \in C :|z+3 i|=4]\).તો \(\sum_{z \in A \cap B}(\operatorname{Re} z-\operatorname{Im} z)=............\)

  1. A \(14\)
  2. B \(13\)
  3. C \(12\)
  4. D \(11\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(14\)

Step-by-step Solution

Detailed explanation

\(\alpha=8-14 i\) \(z=x+i y\) \(a z=(8 x+14 y)+i(-14 x+8 y)\) \(z +\overline{ z }=2 x \quad z -\overline{ z }=2 iy\) Set A: \(\frac{2 i(-14 x+8 y)}{i(4 x y-112)}=1\) \((x-4)(y+7)=0\) \(x=4 \quad \text { or } \quad y=-7\) Set B: \(x^2+(y+3)^2=16\) when \(x=4 \quad y=-3\) when…
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