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JEE Mains · Maths · STD 11 - 7. binomial theoram

દ્રીપદી \(\left(4^{\frac{1}{4}}+5^{\frac{1}{6}}\right)^{120}\) નાં વિસ્તરણમાં સંમેય પદોની સંખ્યા મેળવો.

  1. A \(120\)
  2. B \(21\)
  3. C \(41\)
  4. D \(61\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(21\)

Step-by-step Solution

Detailed explanation

\(\left(4^{1 / 4}+5^{1 / 6}\right)^{120}\) \(T_{r+1}={ }^{120} C_{r}\left(2^{1 / 2}\right)^{120-r}(5)^{r / 6}\) for rational terms \(\mathrm{r}=6 \lambda\,\,\,\, 0 \leq \mathrm{r} \leq 120\) so total no of forms are \(21\)
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