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JEE Mains · Maths · STD 11 - 6. permutation and combination

\(31\) વસ્તુ પૈકી \(10\) સમાન વસ્તુ છે અને \(21\) ભિન્ન વસ્તુ છે તેમાથી \(10\) વસ્તુની પસંદગી કેટલી રીતે કરી શકાય.

  1. A \(2^{20}\)
  2. B \(2^{20}+1\)
  3. C \(2^{21}\)
  4. D \(2^{20}-1\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2^{20}\)

Step-by-step Solution

Detailed explanation

Since \(^{21}{C_0} + .....{ + ^{21}}{C_{10}}{ + ^{21}}{C_{11}} + .....{ + ^{21}}{C_{21}} = {2^{21}}\) \( \Rightarrow \) but we have to select \(10\) objects and \(^{21}{C_0} + .....{ + ^{21}}{C_{10}}{ + ^{21}}{C_{11}} + .....{ + ^{21}}{C_{21}}\)…
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