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JEE Mains · Maths · STD 12 - 6. Application of derivatives

વિધેય  \(f(x)=|5 x-7|+\left[x^{2}+2 x\right]\) ની અંતરાલ \(\left[\frac{5}{4}, 2\right]\) પર મહતમ અને ન્યૂનતમ કિમંતોનો સરવાળો મેળવો. કે જ્યાં \([ t ]\) એ મહતમ પૃણાંક વિધેય છે.

  1. A \(14\)
  2. B \(15\)
  3. C \(13\)
  4. D \(18\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(15\)

Step-by-step Solution

Detailed explanation

\( f(x) =|5 x-7|+\left[x^{2}+2 x\right] \) \(=|5 x-7|+\left[(x+1)^{2}\right]-1 \) Critical points of \(f(x)=\frac{7}{5}, \sqrt{5}-1, \sqrt{6}-1, \sqrt{7}-1, \sqrt{8}-1,2\) Maximum or minimum value of \(f(x)\) occur at critical points or boundary points…
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