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JEE Mains · Maths · STD 11 - 8. sequence and series

\(\left[ { - \frac{1}{3}} \right] + \left[ { - \frac{1}{3} - \frac{1}{{100}}} \right] + \left[ { - \frac{1}{3} - \frac{2}{{100}}} \right] + .....+\left[ { - \frac{1}{3} - \frac{{99}}{{100}}} \right]\) શ્રેણીનો સરવાળો મેળવો જ્યાં \(x \in R\) માટે \([x]\) એ મહતમ પૂર્ણાંક વિધેય છે. 

  1. A \(-135\)
  2. B \(-153\)
  3. C \(-133\)
  4. D \(-131\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-133\)

Step-by-step Solution

Detailed explanation

\(\underbrace {\left[ { - \frac{1}{3}} \right] + \left[ { - \frac{1}{3} - \frac{1}{{100}}} \right] + ... + \left[ { - \frac{1}{3} - \frac{{60}}{{100}}} \right]}_{\left( { - 1} \right)67}\)…
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