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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

યાદી - I ને યાદી - II સાથે જોડો.
સૂચિ - I (આંશિક વ્યુત્પન્ન)સૂચિ - II (થર્મોડાયનેમિક જથ્થો)
(A)\(\left(\frac{\partial \mathrm{G}}{\partial \mathrm{T}}\right)_{\mathrm{P}}\)(I) Cp
(B) \(\left(\frac{\partial \mathrm{H}}{\partial \mathrm{T}}\right)_{\mathrm{P}}\)(II) -S
(C) \(\left(\frac{\partial G}{\partial P}\right)_T\)(III) Cv
(D) \(\left(\frac{\partial \mathrm{U}}{\partial \mathrm{T}}\right)_{\mathrm{V}}\)(IV) V

નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો :

  1. A (A)-(II), (B)-(I), (C)-(III), (D)-(IV)
  2. B (A)-(I), (B)-(II), (C)-(IV), (D)-(III)
  3. C (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  4. D (A)-(II), (B)-(III), (C)-(I), (D)-(IV)
Verified Solution

Answer & Solution

Correct Answer

(C) (A)-(II), (B)-(I), (C)-(IV), (D)-(III)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \because \mathrm{dH}=\mathrm{dq} \text { (at } \mathrm{P}=\text { constant) } \\ & \mathrm{dH}=\mathrm{CpdT}^{\mathrm{dT}} \\ & \left(\frac{\mathrm{dH}}{\mathrm{dT}}\right)_{\mathrm{P}}=\mathrm{C}_{\mathrm{P}} \\ & \mathrm{dU}=\mathrm{dq} \quad \text { (at }…

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