ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

નિર્બળ એસિડની \(HA\)ની સાંદ્રતા \(0.001\, {~mol}\, {~L}^{-1}\) અને વાહકતા \(2.0 \times 10^{-5}\, {~S} \,{~cm}^{-1}\) છે. જો \(\Lambda_{{m}}^{\circ}\) \(({HA})=190 \,{~S} \,{~cm}^{2} {~mol}^{-1}\), \({HA}\)નો આયનીકરણ અચળાંક \(\left({K}_{{a}}\right)\) \(....\,\times 10^{-6}\) બરાબર છે.

  1. A \(18\)
  2. B \(12\)
  3. C \(61\)
  4. D \(14\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(12\)

Step-by-step Solution

Detailed explanation

\(\wedge_{{m}}=1000 \times \frac{\kappa}{{M}}\) \(=1000 \times \frac{2 \times 10^{-5}}{0.001}=20 {~S} {~cm}^{2} {~mol}^{-1}\) \(\Rightarrow \alpha=\frac{\wedge_{{m}}}{\wedge_{{m}}^{\infty}}=\frac{20}{190}=\left(\frac{2}{19}\right)\) \({HA} \rightleftharpoons {H}^{+}+{A}^{-}\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app