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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

Assuming that \({Ba}({OH})_{2}\) is completely ionised in aqueous solution under the given conditions the concentration of \({H}_{3} {O}^{+}\)ions in \(0.005 \,{M}\) aqueous solution of \({Ba}({OH})_{2}\) at \(298\, {~K}\) is \(.....\times 10^{-12}\) \(mol\) \({L}^{-1}\). (Nearest integer)

  1. A \(2\)
  2. B \(1\)
  3. C \(3\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1\)

Step-by-step Solution

Detailed explanation

\({Ba}({OH})_{2} \rightarrow {Ba}^{+2}+2 {OH}^{-} \rightarrow 2 \times 0.005=0.01=10^{-2}\) At \(298\, {~K}:\) in aq. solution \([H3O^{+}][{OH}^{-}]=10^{-14}\) \({\left[{H}_{3} {O}^{+}\right]=\frac{10^{-14}}{10^{-2}}=10^{-12}}\)…
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