JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
Assuming that \(\mathrm{Ba}(\mathrm{OH})_{2}\) is completely ionised in aqueous solution under the given conditions the concentration of \(\mathrm{H}_{3} \mathrm{O}^{+}\)ions in \(0.005 \,\mathrm{M}\) aqueous solution of \(\mathrm{Ba}(\mathrm{OH})_{2}\) at \(298\, \mathrm{~K}\) is \(.....\times 10^{-12}\) \(mol\) \(\mathrm{L}^{-1}\). (Nearest integer)
- A \(2\)
- B \(1\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Ba}(\mathrm{OH})_{2} \rightarrow \mathrm{Ba}^{+2}+2 \mathrm{OH}^{-} \rightarrow 2 \times 0.005=0.01=10^{-2}\) At \(298\, \mathrm{~K}:\) in aq. solution \([H3O^{+}][\mathrm{OH}^{-}]=10^{-14}\)…
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