ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

\(600\,mL\) of \(0.01\,M\,HCl\) ને \(400\,mL\) of \(0.01\,M\,H _2 SO _4\)માં મિશ્ર કરવામાં આવ્યું.તો મિશ્રણની \(pH............\times 10^{-2}\) છે.(નજીકનો પૂર્ણાક) [આપેલ \(\log 2=0.30, \quad \log 3=0.48\) \(\log 5=0.69 \quad \log 7=0.84\) \(\log 11=1.04]\)

  1. A \(185\)
  2. B \(186\)
  3. C \(184\)
  4. D \(183\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(186\)

Step-by-step Solution

Detailed explanation

Total milimoles of \(H ^{+}=(600 \times 0.01)+(400 \times 0.01 \times 2)\) \(=14\) \(\left[ H ^{+}\right]=\frac{14}{1000}=14 \times 10^{-3}\) \(pH =3-\log 14\) \(=1.86\) \(=186 \times 10^{-2}\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app