WBJEE · Physics · Electrostatics
The line \(A A^{\prime}\) is on charged infinite \(A\) conducting plane which is perpendicular to the plane of the paper. The plane has a surface density of charge \(\sigma\) and \(B\) is ball of mass \(m\) with a like charge of magnitude \(q . B\) is connected by string from a point on the line \(A A^{\prime}\). The tangent of angle (0) formed between the line \(A A^{\prime}\) and the string is
- A \(\frac{q \sigma}{2 \varepsilon_{0} m g}\)
- B \(\frac{q \sigma}{4 \pi \varepsilon_{g} m g}\)
- C \(\frac{q \sigma}{2 \pi e_{0} m g}\)
- D \(\frac{q \sigma}{\varepsilon_{0} m g}\)
Answer & Solution
Correct Answer
(D) \(\frac{q \sigma}{\varepsilon_{0} m g}\)
Step-by-step Solution
Detailed explanation
The diagram is as follows The electric field due to charged infinite conducting sheet is \(E=\frac{\sigma}{\varepsilon_{0}}\) Now, force (electric force) on the charged ball is \(F=q E=\frac{q \sigma}{\varepsilon_{0}}\) The resultant of electric force and \(m g\) balance the…
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