WBJEE · Maths · Differential Equations
Let \(\mathrm{y}=\frac{1}{1+\mathrm{x}+\ln \mathrm{x}}\), Then
- A \(x \frac{d y}{d x}+y=x\)
- B \(x \frac{d y}{d x}=y(y \ln x-1)\)
- C \(x^{2} \frac{d y}{d x}=y^{2}+1-x^{2}\)
- D \(x\left(\frac{d y}{d x}\right)^{2}=y-x\)
Answer & Solution
Correct Answer
(B) \(x \frac{d y}{d x}=y(y \ln x-1)\)
Step-by-step Solution
Detailed explanation
Hint: \(x \frac{d y}{d x}=y(y \ln x-1)\)
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