WBJEE · Physics · Gravitation
A body of mass \(m\) is thrown vertically upward with speed \(\sqrt{3} v_e\), where \(v_e\) is the escape velocity of a body from earth surface. The final velocity of the body is
- A 0
- B \(2 v_e\)
- C \(\sqrt{3} v_e\)
- D \(\sqrt{2} \mathrm{v}_{\mathrm{e}}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{2} \mathrm{v}_{\mathrm{e}}\)
Step-by-step Solution
Detailed explanation
\(-\frac{\mathrm{GMm}}{\mathrm{R}}+\frac{1}{2} \mathrm{~m}\left(\sqrt{3} \mathrm{v}_{\mathrm{e}}\right)^2=0+\frac{1}{2} \mathrm{mv}^2, \quad \mathrm{v}=\sqrt{2} \mathrm{v}_{\mathrm{e}}\)
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