WBJEE · Chemistry · d and f Block Elements
The electronic configuration of \(\mathrm{Cu}\) is
- A [Ne] \(3 s^{2}, 3 p^{6}, 3 d^{9}, 4 s^{2}\)
- B [Ne] \(3 s^{2}, 3 p^{6}, 3 d^{10}, 4 s^{1}\)
- C [Ne] \(3 s^{2}, 3 p^{6}, 3 d^{3}, 4 s^{2}, 4 p^{6}\)
- D \([\mathrm{Ne}] 3 \mathrm{s}^{2}, 3 p^{6}, 3 d^{5} \cdot 4 s^{2} \cdot 4 p^{4}\)
Answer & Solution
Correct Answer
(B) [Ne] \(3 s^{2}, 3 p^{6}, 3 d^{10}, 4 s^{1}\)
Step-by-step Solution
Detailed explanation
Atomic number of Cu is 29 . Thus, its electronic configuration can be written as \[ \mathrm{Cu}_{29}=1s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{10}, 4 s^{1} \] (Since, fully filled orbitals are more stable, so one electron from 4 s orbital transfers into \(3 d\) orbital.…
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