WBJEE · Physics · Wave Optics
In a single-slit diffraction experiment, the slit is illuminated by light of two wavelength \(\lambda_1\) and \(\lambda_2\). It is observed that the 2 nd order diffraction minimum for \(\lambda_1\) coincides with the 3 rd diffraction minimum for \(\lambda_2\). Then
- A \(\frac{\lambda_1}{\lambda_2}=\frac{2}{3}\)
- B \(\frac{\lambda_1}{\lambda_2}=\frac{5}{7}\)
- C \(\frac{\lambda_1}{\lambda_2}=\frac{3}{2}\)
- D \(\frac{\lambda_1}{\lambda_2}=\frac{7}{5}\)
Answer & Solution
Correct Answer
(C) \(\frac{\lambda_1}{\lambda_2}=\frac{3}{2}\)
Step-by-step Solution
Detailed explanation
Hint: \(d \sin \theta=\mathrm{n} \lambda\) \[ \begin{aligned} & \mathrm{n}_1 \lambda_1=\mathrm{n}_2 \lambda_2 \\ & \frac{\lambda_1}{\lambda_2}=\frac{\mathrm{n}_2}{\mathrm{n}_1}=3 / 2 \end{aligned} \]
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