WBJEE · Physics · Ray Optics
The distance between an object and a divergent lens is \(\mathrm{m}\) times the focal length of the lens. The linear magnification produced by the lens is
- A \(\mathrm{m}\)
- B \(\frac{1}{\mathrm{~m}}\)
- C \(m+1\)
- D \(\frac{1}{m+1}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{m+1}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{u}=-\mathrm{mf}\) \(\frac{1}{\mathrm{v}}-\frac{1}{(-m f)}=-\frac{1}{f} \Rightarrow \frac{1}{\mathrm{v}}=-\frac{1}{f}\left(1+\frac{1}{m}\right) \Rightarrow-\frac{\mathrm{v}}{\mathrm{u}}=\left(\frac{1}{1+m}\right)\)
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