WBJEE · Physics · Dual Nature of Matter
The work function of Cesium is \(2.27 \mathrm{eV}\). The cut-off voltage which stops the emission of electrons from a cesium cathode irradiated with light of \(600 \mathrm{nm}\) wavelength is
- A \(0.5 \mathrm{V}\)
- B \(-0.2 \mathrm{V}\)
- C \(-0.5 \mathrm{V}\)
- D None of the above
Answer & Solution
Correct Answer
(D) None of the above
Step-by-step Solution
Detailed explanation
Work function of cesium \(=2.27 \mathrm{eV}\) The wavelength of incident light \[ \lambda=600 \mathrm{nm}=600 \times 10^{-9} \mathrm{m} \] The energy of incident photon \(=h v\)…
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