WBJEE · Physics · Center of Mass Momentum and Collision
Centre of mass (C.M.) of three particles of masses \(1 \mathrm{~kg}, 2 \mathrm{~kg}\) and \(3 \mathrm{~kg}\) lies at the point \((1,2,3)\) and C.M. of another system of particles of \(3 \mathrm{~kg}\) and \(2 \mathrm{~kg}\) lies at the point \((-1,3,-2)\). Where should we put a particle of mass \(5 \mathrm{~kg}\) so that the C.M. of entire system lies at the C.M. of the first system ?
- A \((3,1,8)\)
- B \((0,0,0)\)
- C \((1,3,2)\)
- D \((-1,2,3)\)
Answer & Solution
Correct Answer
(A) \((3,1,8)\)
Step-by-step Solution
Detailed explanation
\(\left.\begin{array}{l}6 \mathrm{~kg}[1,2,3] \\ 5 \mathrm{~kg}[-1,3,-2] \\ 5 \mathrm{~kg}[\mathrm{x}, \mathrm{y}, \mathrm{z}]\end{array}\right) \rightarrow(\overline{\mathrm{x}}, \overline{\mathrm{y}}, \overline{\mathrm{z}})=(1,2,3)\)…
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