WBJEE · Chemistry · Structure of Atom
The atomic masses of helium and neon are \(4.0\) and \(20.0\) amu respectively. The value of the de Broglie wavelength of helium gas at \(-73^{\circ} \mathrm{C}\) is \(\mathrm{M}\) times the de Broglie wavelength of neon at \(727^{\circ} \mathrm{C}\). The value of \(\mathrm{M}\) is
- A 5
- B 25
- C \(\frac{1}{5}\)
- D \(\frac{1}{25}\)
Answer & Solution
Correct Answer
(A) 5
Step-by-step Solution
Detailed explanation
\(\lambda_{\mathrm{He}}(200 \mathrm{~K})=\mathrm{M} \times \lambda_{\mathrm{Ne}}(1000 \mathrm{~K})\) \(\left(\lambda=\frac{\mathrm{h}}{\mathrm{m} \cdot \mathrm{v}}\right)\)…
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