WBJEE · Physics · Laws of Motion
Two weights of the mass \(m_{1}\) and \(m_{2}\left(>m_{1}\right)\) are joined by an inextensible string of negligible mass passing over a fixed frictionless pulley. The magnitude of the acceleration of the loads is
- A \(g\)
- B \(\frac{m_{2}-m_{1}}{m_{2}} g\)
- C \(\frac{m_{1}}{m_{2}+m_{1}} g\)
- D \(\frac{m_{2}-m_{1}}{m_{2}+m_{1}} g\)
Answer & Solution
Correct Answer
(D) \(\frac{m_{2}-m_{1}}{m_{2}+m_{1}} g\)
Step-by-step Solution
Detailed explanation
According to the question, we can draw the following diagram Here, \(T\) is the tension in the string. In equilibrium condition. For mass \(m_{1}, \quad T-m_{1} g=m_{1} a\)....(i) For mass \(m_{2}, \quad m_{2} g-T=m_{2} a\)....(ii) After adding Eqs. (i) and (ii), we get…
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