WBJEE · Physics · Electrostatics
A charge \(q\) is placed at one corner of a cube. The electric flux through any of the three faces adjacent to the charge is zero. The flux through any one of the other three faces is
- A \(q / 3 \varepsilon_{0}\)
- B \(q / 6 \varepsilon_{0}\)
- C \(q / 12 \varepsilon_{0}\)
- D \(q / 24 \varepsilon_{0}\)
Answer & Solution
Correct Answer
(D) \(q / 24 \varepsilon_{0}\)
Step-by-step Solution
Detailed explanation
Consider the diagram In above the flux coverage of three face is shown in figure. Which is like a quadrant in any plane. So, flux will be \[ \phi=\frac{1}{4} \times \frac{q}{6 \varepsilon_{0}}=\frac{q}{24 \varepsilon_{0}} \]
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