WBJEE · Physics · Magnetic Effects of Current
An equilateral triangle is made by uniform wires \(A B, B C, C A .\) A current \(I\) enters at \(A\) and leaves from the mid point of \(B C\). If the lengths of each side of the triangle is \(L,\) the magnetic field \(B\) at the centroid \(O\) of the triangle is 
- A \(\frac{\mu_{0}}{4 \pi}\left(\frac{4 L}{L}\right)\)
- B \(\frac{\mu_{0}}{2 \pi}\left(\frac{4 L}{L}\right)\)
- C \(\frac{\mu_{0}}{4 \pi}\left(\frac{2 L}{L}\right)\)
- D zero
Answer & Solution
Correct Answer
(D) zero
Step-by-step Solution
Detailed explanation
The given situation can be shown as The magnetic field at centroid \(O\) = Magnetic field due to left part + Magnetic field due to right part \(\therefore\) \[ \mathrm{B}=\mathrm{B}_{1}+\mathrm{B}_{2}=0 \] (: direction of \(B\) due to both parts is different of \(O\) )
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