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WBJEE · Maths · Application of Derivatives

Let \(f(x)\) be a differentiable function in \([2,7]\). If \(f(2)=3\) and \(f^{\prime}(x) \leq 5\) for all \(x\) in \((2,7),\) then the maximum posaible value of \(f(x)\) at \(x=7\) is

  1. A 7
  2. B 15
  3. C 28
  4. D 14
Verified Solution

Answer & Solution

Correct Answer

(C) 28

Step-by-step Solution

Detailed explanation

Given, \(\quad f^{\prime}(x) \leq 5\) \(\frac{f(7)-f(2)}{x-2} \leq 5\) (by Lagrange mean value theorem] \(\begin{array}{ll}\Rightarrow & \frac{f(7)-3}{7-2} \leq 5 \\ \Rightarrow & f(7) \leq 5(7-2)+3 \\ \therefore & f(7) \leq 28\end{array}\)