WBJEE · Physics · Magnetic Effects of Current
A charged particle in a uniform magnetic field \(B=B_0 \hat{k}\) starts moving from the origin with velocity \(v=3 \hat{i}+4 \hat{k}\) m/s. The trajectory of the particle and the time \(t\) at which it reaches \(2 \mathrm{~m}\) above \(x-y\) plane are,
- A Circular path, \(\frac{1}{2}\) sec.
- B Helical path, \(\frac{1}{2}\) sec.
- C Circular path, \(\frac{2}{3}\) sec.
- D Helical path, \(\frac{2}{3}\) sec.
Answer & Solution
Correct Answer
(B) Helical path, \(\frac{1}{2}\) sec.
Step-by-step Solution
Detailed explanation
Hint : Velocity along z-direction will be const. \(\mathrm{t}=\frac{\mathrm{s}}{V_z}=\frac{2}{4}=\frac{1}{2} \mathrm{sec}\) Path will be helical.
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