WBJEE · Chemistry · Chemical Equilibrium
Equilibrium constants for the following reactions at \(1200 \mathrm{K}\) are given
\(2 \mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)\)
\(K_{1}=6.4 \times 10^{-8}\)
\(2 \mathrm{CO}_{2}(g) \rightleftharpoons 2 \mathrm{CO}(g)+\mathrm{O}_{2}(g)\)
\(K_{2}=1.6 \times 10^{-6}\)
The equilibrium constant for the reaction? \(\mathrm{H}_{2}(g)+\mathrm{CO}_{2}(g) \rightleftharpoons \mathrm{CO}(g)+\mathrm{H}_{2} \mathrm{O}(g)\)
at \(1200 \mathrm{K}\) will be
- A 0.05
- B 20
- C 0.2
- D 5
Answer & Solution
Correct Answer
(D) 5
Step-by-step Solution
Detailed explanation
For the given reactions, \(2 \mathrm{H}_{2} \mathrm{O} \rightleftharpoons 2 \mathrm{H}_{2}+\mathrm{O}_{2}, K_{1}=6.4 \times 10^{-8}\) or, \(\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{H}_{2}+\frac{1}{2} \mathrm{O}_{2}, K_{1}^{\prime}=\sqrt{K_{1}}\) or…
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