WBJEE · Physics · Current Electricity
One \(\mathrm{Kg}\) of copper is drawn into a wire of \(1 \mathrm{~mm}\) diameter and a wire of \(2 \mathrm{~mm}\) diameter. The resistance of the two wires will be in the ratio
- A \(2: 1\)
- B \(1: 2\)
- C \(16: 1\)
- D \(4: 1\)
Answer & Solution
Correct Answer
(C) \(16: 1\)
Step-by-step Solution
Detailed explanation
Mass \(=\left(\pi \mathrm{r}_1^2 \ell_1\right) \sigma\) (Ist wire)…
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