WBJEE · Physics · Semiconductors
A Zener diode having break-down voltage \(5.6 \mathrm{V}\) is connected in reverse bias with a battery of emf \(10 \mathrm{V}\) and a resistance of \(100 \Omega\) in series. The current flowing through the Zener diode is
- A \(88 \mathrm{mA}\)
- B \(0.88 \mathrm{mA}\)
- C \(4.4 \mathrm{mA}\)
- D \(44 \mathrm{mA}\)
Answer & Solution
Correct Answer
(D) \(44 \mathrm{mA}\)
Step-by-step Solution
Detailed explanation
Breakdown voltage of Zener diode \(=5.6 \mathrm{V}\) Voltage of source \(=10 \mathrm{V}\) Potential difference \(\Delta V=(10-5.6) \mathrm{V}=4.4 \mathrm{V}\) Resistance of circuit \(=100 \Omega\) The current passing through the Zener diode…
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