WBJEE · Physics · Motion In One Dimension
A bullet on penetrating \(30 \mathrm{cm}\) into its target loses its velocity by \(50 \%\). What additional distance will it penetrate into the target before it comes to rest?
- A \(30 \mathrm{cm}\)
- B \(20 \mathrm{cm}\)
- C \(10 \mathrm{cm}\)
- D \(5 \mathrm{cm}\)
Answer & Solution
Correct Answer
(C) \(10 \mathrm{cm}\)
Step-by-step Solution
Detailed explanation
Given \(S=30 \mathrm{cm}=30 \times 10^{-2} \mathrm{m}\) and loss in velocity is \(50 \%\) Equation of motion \[ v^{2}=u^{2}+2 a s \] Here, \(\frac{u^{2}}{4}=u^{2}+2 a \times 30 \times 10^{-2}\) \[ 0=\frac{u^{2}}{4}+3 a \times x \] On solving Eqs. (i) and (ii), we get…
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