WBJEE · Physics · Waves and Sound
The equation of stationary wave along a stretched string is given by \(y=5 \sin \frac{\pi x}{3} \cos 40 \pi t\). Here x and y are in cm and t in second. The separation between two adjacent nodes is
- A 1.5 cm
- B 3 cm
- C 6 cm
- D 14 cm
Answer & Solution
Correct Answer
(B) 3 cm
Step-by-step Solution
Detailed explanation
\(\mathrm{y}=5 \sin \left(\frac{\pi}{3} \mathrm{x}\right) \cos (40 \pi \mathrm{t}), \omega=40 \pi \mathrm{k}=3 \mathrm{~cm}, \lambda=\frac{2 \pi}{\mathrm{k}}=6 \mathrm{~cm}\) Separation between nodes \(=\frac{\lambda}{2}=3 \mathrm{~cm}\)
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