WBJEE · Physics · Motion In Two Dimensions
A bullet is fired with a velocity u making an angle of \(60^{\circ}\) with the horizontal plane. The horizontal component o the velocity of the bullet when it reaches the maximum height is
- A \(\mathrm{u}\)
- B \(0\)
- C \(\frac{\sqrt{3 u}}{2}\)
- D \(\frac{\mathrm{u}}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{u}}{2}\)
Step-by-step Solution
Detailed explanation
Horizontal velocity would be constant so the value of velocity at the highest point will be \(u / 2\)
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