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WBJEE · Physics · Magnetic Effects of Current

A straight wire is placed in a magnetic field that varies with distance \(x\) from origin as \(\vec{B}=B_0\left(2-\frac{x}{a}\right) \hat{k}\). Ends of wire are at \((a, 0)\) and \((2 a, 0)\) and it carries a current \(\mathrm{I}\). If force on wire is \(\vec{F}=\mathrm{IB}_0\left(\frac{k a}{2}\right) \hat{\mathrm{j}}\), then value of \(k\) is

  1. A 1
  2. B 5
  3. C \(-1\)
  4. D \(\frac{1}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-1\)

Step-by-step Solution

Detailed explanation

\(\overrightarrow{\mathrm{dF}}=\mathrm{Idx} \times \overrightarrow{\mathrm{B}}=\operatorname{Idx} \hat{\mathrm{i}} \times \mathrm{B} \hat{\mathrm{k}}=\operatorname{IdxB}(-\hat{\mathrm{j}})\)…