WBJEE · Physics · Electrostatics
A negative charge is placed at the midpoint between two fixed equal positive charges, separated by a distance \(2 d\). If the negative charge is given a small displacement \(x(x< < a)\) perpendicular to the line joining the positive charges, how the force \((F)\) developed on it will approximately depend on \(x ?\)
- A \(F \propto x\)
- B \(F \propto \frac{1}{x}\)
- C \(F \propto x^{2}\)
- D \(F \propto \frac{1}{x^{2}}\)
Answer & Solution
Correct Answer
(A) \(F \propto x\)
Step-by-step Solution
Detailed explanation
According to the question, Force experienced by the charge \(-q\) due to charge \(Q\)…
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