WBJEE · Maths · Straight Lines
Number of points having distance \(\sqrt{5}\) fron the straight line \(x-2 y+1=0\) and a distance \(\sqrt{13}\) from the line \(2 x+3 y-1=0,\) is
- A 1
- B 2
- C 4
- D 5
Answer & Solution
Correct Answer
(C) 4
Step-by-step Solution
Detailed explanation
Let the point be \((h, k)\) Then, \(\left|\frac{h-2 k+1}{\sqrt{1^{2}+(-2)^{2}}}\right|=\sqrt{5}\) \(h-2 k+1=\pm 5\) Also, \(\left|\frac{2 h+3 k-1}{\sqrt{2^{2}+3^{2}}}\right|=\) \(\Rightarrow \quad 2 h+3 k-1=\pm 13\) On solving Eqs (i) and (ii), we get four points So. there are…
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