WBJEE · Physics · Work Power Energy
A bullet of mass \(m\) travelling with a speed \(v\) hits a block of mass \(M\) initially at rest and gets embedded in it. The combined system is free to move and there is no other force acting on the system. The heat generated in the process will be
- A Zero
- B \(\frac{m v^{2}}{2}\)
- C \(\frac{M m v^{2}}{2(M-m)}\)
- D \(\frac{m M v^{2}}{2(M+m)}\)
Answer & Solution
Correct Answer
(D) \(\frac{m M v^{2}}{2(M+m)}\)
Step-by-step Solution
Detailed explanation
Mass of bullet \(=m_{1}=m\) Initial speed of bullet \(=u_{1}=v\) Mass of block \(=m_{2}=M\) Initial speed of block \(=u_{2}=0\) Let the common velocity of the bodies after collision \(=V\) According to conservation of linear momentum…
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