WBJEE · Maths · Continuity and Differentiability
Let \(f(x)=|x-\alpha|+|x-\beta|\), where \(\alpha, \beta\) are the roots of the equation \(x^2-3 x+2=0\). Then the number of points in \([\alpha, \beta]\) at which \(f\) is not differentiable is
- A \(2\)
- B \(0\)
- C \(1\)
- D infinite
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
\(\because\) Two distinct real roots 1,2 \(f(x)=|x-1|+|x-2|\) \(\therefore\) Differentiable in \([1,2]\)
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