WBJEE · Maths · Vector Algebra
Let \(\vec{a}, \vec{b}, \vec{c}\) be unit vectors. Suppose \(\vec{a} \cdot \vec{b}=\vec{a} \cdot \vec{c}=0\) and the angle between \(\vec{b}\) and \(\vec{c}\) is \(\frac{\pi}{6}\). Then \(\vec{a}\) is
- A \(\overrightarrow{\mathrm{b}} \times \overrightarrow{\mathrm{c}}\)
- B \(\overrightarrow{\mathrm{c}} \times \overrightarrow{\mathrm{b}}\)
- C \(\vec{b}+\vec{c}\)
- D \(\pm 2(\vec{b} \times \vec{c})\)
Answer & Solution
Correct Answer
(D) \(\pm 2(\vec{b} \times \vec{c})\)
Step-by-step Solution
Detailed explanation
\(\overline{\mathrm{a}} \perp \overline{\mathrm{b}}\) & \(\overline{\mathrm{a}} \perp \overline{\mathrm{c}}\) Let \(\overline{\mathrm{a}}= \pm \lambda(\overline{\mathrm{b}} \times \overline{\mathrm{c}})\)…
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