WBJEE · Chemistry · Chemical Kinetics
Consider, the radioactive disintegration \({ }_{82} A^{210} \rightarrow B \rightarrow C \rightarrow{ }_{82} D^{206}\), The sequence of emission can be
- A \(\beta, \beta, \beta\)
- B \(\alpha, \alpha, \beta\)
- C \(\beta, \beta, \gamma\)
- D \(\beta, \beta, \alpha\)
Answer & Solution
Correct Answer
(D) \(\beta, \beta, \alpha\)
Step-by-step Solution
Detailed explanation
Given, \(82^{A^{210}} \longrightarrow B \longrightarrow C \longrightarrow{ }_{82} D^{206}\) i.e. difference in mass no. between \(A\) and \(D\) is of 4 units i.e., mass no. is decreased by 4 units while atomic no. remains the same, i.e. 82 for \(A\) and \(D\). Also, (i) On…
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