WBJEE · Maths · Quadratic Equation
The quadratic expression \((2 x+1)^{2}-p x+q \neq 0\) for any real \(x,\) if
- A \(p^{2}-16 p-8 q < 0\)
- B \(p^{2}-8 p+16 q < 0\)
- C \(p^{2}-8 p-16 q < 0\)
- D \(p^{2}-16 p+8 q < 0\)
Answer & Solution
Correct Answer
(C) \(p^{2}-8 p-16 q < 0\)
Step-by-step Solution
Detailed explanation
Given equation is \((2 x+1)^{2}-p x+q \neq 0\) \[ \begin{array}{lr} \Rightarrow & 4 x^{2}+4 x+1-p x+q \neq 0 \\ \Rightarrow & 4 x^{2}+(4-p) x+(1+q) \neq 0 \end{array} \] Now. D \( < \) 0 \(\Rightarrow \quad(4-p)^{2}-4(4)(1+q) < 0\) \(\Rightarrow \quad 16-8 p+p^{2}-16-16 q < 0\)…
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