WBJEE · Maths · Inverse Trigonometric Functions
If \(\sin ^{-1}\left(x-\frac{x^{2}}{2}+\frac{x^{3}}{4}-\frac{x^{4}}{8}+\ldots\right)=\frac{\pi}{6},\) where \(|x| < 2\) then the value of \(x\) is
- A \(\frac{2}{3}\)
- B \(\frac{3}{2}\)
- C \(-\frac{2}{3}\)
- D \(-\frac{3}{2}\)
Answer & Solution
Correct Answer
(A) \(\frac{2}{3}\)
Step-by-step Solution
Detailed explanation
We have, \(\sin ^{-1}\left(x-\frac{x^{2}}{2}+\frac{x^{3}}{4}-\frac{x^{4}}{8}+\ldots\right)=\frac{\pi}{6}\) \(\Rightarrow \sin ^{-1}\left(\frac{x}{1-\left(\frac{-x}{2}\right)}\right)=\frac{\pi}{6} \quad\left[\because S_{\infty}=\frac{a}{1-r}\right]\)…
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