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WBJEE · Maths · Inverse Trigonometric Functions

If \(\sin ^{-1}\left(x-\frac{x^{2}}{2}+\frac{x^{3}}{4}-\frac{x^{4}}{8}+\ldots\right)=\frac{\pi}{6},\) where \(|x| < 2\) then the value of \(x\) is

  1. A \(\frac{2}{3}\)
  2. B \(\frac{3}{2}\)
  3. C \(-\frac{2}{3}\)
  4. D \(-\frac{3}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{2}{3}\)

Step-by-step Solution

Detailed explanation

We have, \(\sin ^{-1}\left(x-\frac{x^{2}}{2}+\frac{x^{3}}{4}-\frac{x^{4}}{8}+\ldots\right)=\frac{\pi}{6}\) \(\Rightarrow \sin ^{-1}\left(\frac{x}{1-\left(\frac{-x}{2}\right)}\right)=\frac{\pi}{6} \quad\left[\because S_{\infty}=\frac{a}{1-r}\right]\)…