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WBJEE · Maths · Functions

Let \(f: R \rightarrow R\) be defined as \(f(x)=\frac{x^{2}-x+4}{x^{2}+x+4}\). Then, range of the function \(f(x)\) is

  1. A \(\left[\frac{3}{5}, \frac{5}{3}\right]\)
  2. B \(\left(\frac{3}{5}, \frac{5}{3}\right)\)
  3. C \(\left(-\infty, \frac{3}{5}\right) \cup\left(\frac{5}{3}, \infty\right)\)
  4. D \(\left[-\frac{5}{3},-\frac{3}{5}\right]\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\left[\frac{3}{5}, \frac{5}{3}\right]\)

Step-by-step Solution

Detailed explanation

Let \(y=\frac{x^{2}-x+4}{x^{2}+x+4}\) \(\Rightarrow \quad x^{2} y+x y+4 y=x^{2}-x+4\) \(\Rightarrow(y-1) x^{2}+(y+1) x+4 y-4=0\) For \(x\) to be real, discriminant of the above quadratic equation should be greater than equal to 0…