WBJEE · Physics · Thermodynamics
Consider the P-V diagram for 1 mole of an ideal monatomic gas shown in the figure. Which of the following statements is/are true?
- A The change in internal energy for the whole process is zero
- B Heat is rejected during the process
- C Change in internal energy for process \(A \rightarrow B\) is \(-\frac{3}{2} P_{0} V_{0}\)
- D Work done by the gas during the entire process is \(2 \mathrm{P}_{0} \mathrm{~V}_{0}\)
Answer & Solution
Correct Answer
(C) Change in internal energy for process \(A \rightarrow B\) is \(-\frac{3}{2} P_{0} V_{0}\)
Step-by-step Solution
Detailed explanation
\[ \begin{array}{l} \Delta \mathrm{U}=\mathrm{n} \mathrm{Cv} \Delta \mathrm{T} \\ \Delta \mathrm{T}=\frac{\mathrm{P}_{\mathrm{c}} \mathrm{V}_{\mathrm{c}}}{\mathrm{nR}}-\frac{\mathrm{P}_{\mathrm{A}} \mathrm{V}_{\mathrm{A}}}{\mathrm{nR}}=0 \end{array} \] Hence…
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