WBJEE · Physics · Wave Optics
In Young's double slit experiment the two slits are d distance apart. Interference pattern is observed on a screen at a distance D from the slits. A dark fringe is observed on the screen directly opposite to one of the slits. The wavelength of light is
- A \(\frac{\mathrm{D}^2}{2 \mathrm{~d}}\)
- B \(\frac{\mathrm{d}^2}{2 \mathrm{D}}\)
- C \(\frac{\mathrm{D}^2}{\mathrm{~d}}\)
- D \(\frac{\mathrm{d}^2}{\mathrm{D}}\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{d}^2}{\mathrm{D}}\)
Step-by-step Solution
Detailed explanation
Hints: \(\mathrm{n}^{\text {th }}\) Dark fringe \(\begin{aligned} & (2 n-1) \frac{D \lambda}{2 d}=\frac{d}{2} \\ & \lambda=\frac{d^2}{(2 n-1) D}=\frac{d^2}{D} \quad[\text { for } n=1] \end{aligned}\)
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