WBJEE · Maths · Sequences and Series
Given that \(n\) numbers of arithmetic means are inserted between two sets of numbers \(a, 2 b\) and \(2 a, b\) where \(a, b \in R\). Suppose further that the mih means between these sets of numbers are same, then the ratio \(a\) : \(b\) equals
- A \(n-m+1: m\)
- B \(n-m+1: n\)
- C \(n: n-m+1\)
- D \(m: n-m+1\)
Answer & Solution
Correct Answer
(D) \(m: n-m+1\)
Step-by-step Solution
Detailed explanation
\(\quad 2 b=(n+2)\) th form \(=a+(n+2-1) d\) \(2b=a+(n+1) d\) \(\Rightarrow \quad d=\frac{b-2 a}{n+1}\) \(\therefore m\) th mean \(=2 t+m\left(\frac{b-2 a}{n+1}\right)\) and also, \(\quad b=(n+2)\) th form…
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