WBJEE · Chemistry · Electrochemistry
A conductivity cell has been calibrated with
\(0.01 \mathrm{M} \quad 1: 1\) electrolyte solution (specific conductance, \(k=1.25 \times 10^{-3} \mathrm{S} \mathrm{cm}^{-1}\) ) in the cell and the measured resistance was \(800 \Omega\) at \(25^{\circ} \mathrm{C} .\) The cell constant will be
- A \(1.02 \mathrm{cm}^{-1}\)
- B \(0.102 \mathrm{cm}^{-1}\)
- C \(1.00 \mathrm{cm}^{-1}\)
- D \(0.5 \mathrm{cm}^{-1}\)
Answer & Solution
Correct Answer
(C) \(1.00 \mathrm{cm}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, \(\mathrm{K}=1.25 \times 10^{-3} \mathrm{S} \mathrm{cm}^{-1}\) \[ \rho=\frac{1}{\mathrm{x}}=\frac{1}{1.25 \times 10^{-3}} \mathrm{S}^{-1} \mathrm{cm} \] From \[ \begin{aligned} R &=\rho \frac{1}{A} \\ 800 &=\frac{1}{1.25 \times 10^{-3}} \times \frac{1}{A} \end{aligned} \]…
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