WBJEE · Chemistry · Ionic Equilibrium
The solubility of \(\mathrm{Ca}_3\left(\mathrm{PO}_4\right)_2\) in water is y moles / litre. Its solubility product is
- A \(6 y^4\)
- B \(36 y^4\)
- C \(64 y^5\)
- D \(108 \mathrm{y}^5\)
Answer & Solution
Correct Answer
(D) \(108 \mathrm{y}^5\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {Hints: } \mathrm{Ca}_3\left(\mathrm{PO}_4\right)_2(\mathrm{~s}) \rightleftharpoons 3 \underset{3 \mathrm{~s}}{\mathrm{Ca}^{2+}}(\mathrm{aq})+\underset{2 \mathrm{~s}}{2 \mathrm{PO}_4}{ }^{3-}(\mathrm{aq}) \\ &…
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