WBJEE · Chemistry · General Organic Chemistry
The most contributing tautomeric enol form of \(\mathrm{MeCOCH}_{2} \mathrm{CO}_{2} \mathrm{Et}\) is
- A \(\mathrm{CH}_{2}=\mathrm{C}(\mathrm{OH}) \mathrm{CH}_{2} \mathrm{CO}_{2} \mathrm{Et}\)
- B \(\mathrm{MeC}(\mathrm{OH})=\mathrm{CHCO}_{2} \mathrm{Et}\)
- C MeCOCH = C(OH)OEt
- D \(\mathrm{CH}_{2}=\mathrm{C}(\mathrm{OH}) \mathrm{CH}=\mathrm{C}(\mathrm{OH}) \mathrm{OEt}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{MeC}(\mathrm{OH})=\mathrm{CHCO}_{2} \mathrm{Et}\)
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