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WBJEE · Physics · Thermal Properties of Matter

22320 cal of heat is supplied to 100 g of ice at \(0^{\circ} \mathrm{C}\). If the latent heat of fusion of ice is 80 cal \(\mathrm{g}^{-1}\) and latent heat of vaporization of water is 540 cal \(\mathrm{g}^{-1},\) the final amount of water thus obtained and its temperature respectively
are

  1. A \(8 \mathrm{g}, 100^{\circ} \mathrm{C}\)
  2. B \(100 \mathrm{g} ,90^{\circ} \mathrm{C}\)
  3. C \(92 \mathrm{g}, 100^{\circ} \mathrm{C}\)
  4. D \(82 \mathrm{g}, 100^{\circ} \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(8 \mathrm{g}, 100^{\circ} \mathrm{C}\)

Step-by-step Solution

Detailed explanation

Heat required to convert ice to water at \(100^{\circ} \mathrm{C}\) \[ Q=m \times L+m s \Delta T=18000 \mathrm{cal} \] Amount of heat left \(=4320 \mathrm{cal}\) \[ \begin{array}{l} m \times L=4320 \\ m=8 g \text { steam } \end{array} \]